The H2SO4 is a di-protic acid, i.e. It has actually 2 hydrogens (H+) that deserve to react through the OH- indigenous KOH. So, it stands to reason that it will take 2 KOH for each 1 H2SO4. Right?

You are watching: Write the balanced molecular equation for the neutralization reaction between h2so4 and koh


This is a neutralization reaction and also a dual displacement reaction. Therefore, we can predict the commodities by composing each that our reactants out together the constituent ions that exist as soon as they dissociate in aqueous solution and then convert the anion and cation partners:
When the cations and ions in solution switch partners,H+ joins v OH- to type water (H2O), and K+ joins v SO42- to because that K2SO4.
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