The price is D) Calculate the probability the a child having actually either sickle-cell anemia or cystic fibrosis if parents are each heterozygous for both. The enhancement rule is supplied to calculate the probability of one of the occasions from multiple pathways. If you desire that only among the occasions happens, girlfriend will usage the addition rule. In a instance when you desire to calculation the possibility of a child having actually EITHER sickle-cell anemia OR cystic fibrosis, friend will use THE addition RULE.For example, in explain B) you will not use this rule because there is no either/or, but both/and. In case, B) friend would usage the multiplication rule.

You are watching: Which of the following calculations require that you utilize the addition rule?



Answer from: liddopiink1
1. P(black and yellow)

Answer from: jailynleffel8

3/8

Explanation:

I think ns can assist with completing the question.

Above every punnet square, the genotypes that the parents were offered right? something favor this:

Parent 1 hair genotype: Ff parental 1 eye genotype: Ee

Parent 2 fur genotype: Ff parent 2 eye genotype: ee

F f E e

F FF Ff e Ee ee

f Ff ff e Ee ee

Probability that black fur if leading is: Probability the red eyes:

3/4 2/4= 1/2

Probability of a trait combination such as black color fur and also red eye is

3/4*1/2 = 3/8.



Answer from: alishakira690

30% chance

Step-by-step explanation:



Answer from: Vishal123180

5/12

7/12

125/36 = 3,47%

50/11 = 4,54%

Step-by-step explanation:

Probability a black color sock is selected as soon as a human chooses 1 amount say = 5/12

Probability a white or brown sock is selected once a human chooses 1 sock =

7/12

Probability a human chooses 3 socks and selects a white first, a black color second, and a brown critical if the socks are replace = (4/12 * 5/12 * 3/12)*100 =125/36 = 3,47%

Pobability a human being chooses 3 socks and selects a white first, a black color second, and also a brown critical if the socks are NOT replace = (4/12 * 5/11 * 3/ 10)*100 = 50/11 = 4,54%



Answer from: DragonLovely

Probability is 2/5 or 40%.

Step-by-step explanation:

4/(4+2) = 4/6 = 2/3 first black pen is chosen.

3/5 - second pen is liked without replacement.

2/3 *3/5= 2/5 - the probability a black color pen was chosen, and also then one more black pen without replacement.

2/5*100 % = 40 %


Answer from: DeonDub3106

recessive

Explanation:


Answer from: aaliyahnv07

The required probability is 1/8.

Step-by-step explanation:

In a standard deck cards there room 13 spades , 13 clubs, 13 hearts and also 13 diamonds.

Total cards =

*

The spades and also the clubs room black and the hearts and the diamonds are red.

Means 26 cards space red and also 26 cards are black.

Now, 1 heart card deserve to be drawn from a fill of 13 love cards in 13C1 methods or 13C1=13

And 1 card have the right to be attracted from a pack of 52 cards in 52C1 methods or 52C1=52

So, the probability of illustration a heart card from 52 cards is

*

Similarly, 1 black card can be drawn from a fill of 26 black color cards in 26C1 methods or 26C1=26

And 1 card can be drawn from 52 cards in 52C1 ways or 52C1=52

Therefore, the probability of illustration a black card indigenous a load of 52 cards is

*

Hence, the probability (combined) is =

*


Answer from: lekaje2375

Total number of ways to select 2 blouses = 11*10= 110

P(black and also yellow) = (4C1 * 2C1)/110 = 8/110

P(green and green) = 1/110


Answer from: alexshakim8893
Black card 26 out of 52 or 1/2 or 50% chance. As much as it gift a heart the odds walk to 13 out of 52 or 25%.

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