The wait in a room has actually a push of 1 atm, a dry-bulb temperature of 24°C, and also a wet-bulb temperature of 17°C. Utilizing the psychro

Given that

Dry-bulb temperature(T) =24°C

Wet-bulb temperature(Tw) = 17°C

Pressure ,P = 1 atm

As we know that psychrometric graph are drawn at consistent pressure.

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From the diagram

ω= specific humidity

Lets take these two lines Dry-bulb temperature(T) line and Wet-bulb temperature(Tw) reduced at allude P

From graph at allude P


Specific humidity,ω = 0.00922 kg/kg


The enthalpy ( h)

h=47.59 KJ/kg


The family member humidity, RH

RH= 49.58 %


Specific volume ,

v= 0.853 m³/kg


After it"s lengthy use, the bridge repeatedly undergoes through alternative strains. In result, the elastic stamin of the bridge gets reduced. When the process goes top top the bridge renders elastic fatigue and a permanent adjust happens which renders it collapse which is the factor why bridges are declared unsafe ~ a lengthy use​ :)

Indicate the an outcome of every of the following unit vector cross assets (unit vector hat-symbols not shown): . Kxi = . Jxi= -jxk


The overcome product of 2 vectors is offered by


Where, θ it is in the angle in between the 2 vectors and also \widehatn it is in the unit vector follow me the direction of overcome product of 2 vectors.

Here, K x i = - j

As K is the unit vector follow me Z axis, i is the unit vector follow me X axis and j be the unit vector along axis.

The direction of cross product of 2 vectors is given by the ideal hand palm rule.

So, k x ns = j

j x ns = - k

- j x k = - ns

i x ns = 0

A platinum cable is used to determine the melting allude of indium. The resistance of the platinum cable is 2.000 Ω in ~ 20°C and inc

The melting point of indium is 157.436 levels Celsius.


The resistance that the platinum wire, R1 = 2

The temperature at R1 is, T1 = 20 degrees Celsius.

The increased resistance, R2 = 3.072

Let the temperature at 3.072 = T2

Now find the temperature in ~ which the indium start melting.

We recognize that α = ( R2 - R1 ) / < R1 × ( T2 - T1 ) >

Given, α = 3.9 x 10^-3/ levels Celsius.

T2- T1 = ( R2 - R1 ) / R1 α

T2 – T1 = (3.072 – 2) / (2 × 3.9 x 10^-3)

T2 – T1 = 137.436

T2 = T1 + 137.436

T2 = 20 + 137.436

T2 = 157.436 level Celsius

5 0
11 months ago

The wait in this room is composed of many tiny, elevation molecules. You deserve to be certain that these air molecule won"t all shift
beks73 <17>

(B) be very unlikely and also therefore violate the second law the thermodynamics.

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This procedure is highly unlikely and also if happens would violet the 2nd law of thermodynamics.

The laws of movement do not ascendancy out a move to one side of the room of every the waiting molecules. Yet it would certainly be exceptionally unlikely to take place that. The 2nd law the thermodynamics says that the universe responds to scenarios that become much more and much more likely, no improbable.

8 0
11 month ago
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