I assumed it to be correct since sqrt is opposing of multiplying by a number, so i figured by multiplying by a number it would certainly balance out and also be that number normally, yet when i tried it v my Python calculator making use of 3 i got:

sdrta.net.sqrt(3) * 3 5.196152422706632  \$egingroup\$ \$sqrt x\$ is the number satisfying \$sqrt x sqrt x = x\$; it's not the the contrary of multiply by \$x\$. \$endgroup\$
In general, no. Because \$sqrt x\$ is equal to \$x^1/2\$, your equation is the exact same as \$x^3/2 = x\$, only \$x = 0, 1\$ occupational as solutions If you desire to solve for the equation\$\$xsqrtx = x\$\$then you have\$\$x (sqrtx-1) =0 Rightarrow x = 0, ext or sqrtx=1, ext i.e. x = 1\$\$ The multiplicative station (the "opposite" in her question) of a non-zero number \$x\$ is the reciprocal, \$frac1x\$. Multiply these 2 together offers instead \$x imes frac1x = 1\$.

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