Given the the density of Hg(l) in ~ 0°C is around 14 g mL-1, i m sorry of the following is closest come the volume of one mole that Hg(l)
From the question, we\"ve been told that the the the density of Hg(l) at 0°C is about 14 g mL-1.
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14g = 1mL
We need to note the atomic load of mercury = 200.59.
Therefore, 1 mol Hg = 200.59 g
Therefore, the sdrta.net that is closest to the volume the one mole that Hg(l) in ~ this temperature will certainly be:
= 14.3 mL
= 14mL approximately
What fraction of the gas phase molecules initially existing for 1.0 atm in the room are present at 1.0×10−10 torr?
The portion of gas step molecules is calculated by the department of final pressure come the initial pressure.
Here, initial push = 1.0 atm
final pressure =
First, transform torr into atm
1 atm = 760 torr
final press =
Now, placed the worth of initial and also final press in formula (1)
Thus, portion of the gas step molecules =
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Substitution of one amino group on the para place of acetophenone move the cjo frequency from about 1685 to 1652 cm−1 , wher
Here\"s what ns get.
The frequency of a vibration counts on the strength of the link (the force constant).
The more powerful the bond, the more energy is needed for the vibration, so the frequency (f) and the wavenumber increase.
Resonance interactions through the fragrant ring offer the C=O shortcut in acetophenone a mix of single- and also double-bond character, and the shortcut frequency = 1685 cm⁻¹.
The +R result of the amino team increases the single-bond character of the C=O bond. The bond lengthens, so it i do not care weaker.
The vibrational energy decreases, for this reason wavenumber decreases come 1652 cm⁻¹.
The nitro group puts a partial hopeful charge on C-1. The -I effect withdraws electron from the acetyl group.
As electron density moves towards C-1, the twin bond personality of the C=O team increases.
The bond length decreases, so the bond i do not care stronger, and also wavenumber boosts to 1693 cm¹.
9 month ago
In one experiment, 170.9 g that C2H4 to be reacted v an excess of O2, 164.1 g that CO2 is produced.
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In this case, offered the reaction, the molar fixed of ethene is 28 g/mol and also the molar mass of carbon dioxide is 44 g/mol. With that info we compute the theoretical yield considering a 1:2 molar proportion respectively between them:
Thus, us compute the percent yield v the offered grams the carbon dioxide:
6 month ago
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