Valence electrons space the electrons existing in the outermost covering of of one atom.

You are watching: Compared with group 2a elements group 6a elements have

Elements of group 6A room oxygen, sulfur, selenium, tellurium, and polonium.

As all these facets are of group 6A therefore, lock contain 6 valence electrons.

On the various other hand, facets of team 2A space beryllium, magnesium, calcium, strontium, barium and radon.

As every these are team 2A facets therefore, lock contain 2 valence electrons.

thus, we can conclude that compared with team 6A elements, group 2A elements have fewer valence electrons.


melisa1 <442>9 month ago
6 0
The periodic table of facets is split into eight groups, excluding the change metals. The facets in these teams are inserted in their corresponding positions due to the variety of valence electron they have. The valence electron of an atom room the electron in the outermost covering of the atom. Thus, the atoms of the facets in group 1 have actually 1 valence electron, those in group 2 have actually 2 valence electrons and so on. For this reason an aspect in team 6 will have 6 valence electrons, i beg your pardon is much more than that of an facet from team 2. Therefore, the is D. Fewer valence electrons.
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Use Lewis theory to attract the structure of the link containing 1 carbon and also 4 chlorine atoms. What would certainly you uncover surrounding
Nikolay <14> : The correct option is, (B) no double bonds.

Explanation :

Lewis-dot structure : It mirrors the bonding in between the atoms of a molecule and it additionally shows the unpaired electrons current in the molecule.

In the Lewis-dot framework the valance electrons are displayed by "dot".

As us are offered that the framework of the compound containing 1 carbon and also 4 chlorine atoms.

Thus, the molecule is,


As we know that carbon has "4" valence electrons and chlorine has actually "7" valence electrons.

Therefore, the total variety of valence electron in

= 4 + 4(7) = 32

According come Lewis-dot structure, there are 8 variety of bonding electrons and 24 variety of non-bonding electrons.

From the Lewis-dot structure we conclude the there space 4 solitary bonds are bordering the central atom of this ion there is no double or triple bonds space present.

Hence, the correct choice is, (B) no twin bonds.


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To uncover the specific heat that a material, an initial look in ~ the units. Over there is power per unit mass every unit temperature. So if us are provided an lot of energy appllied come an object, the mass and how much the temperature of the object rises, we can calculate that specifc warmth by separating the energy by both the mass and also the temperature, yet don"t forget to store the devices as lock are:

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