This means that the elements with the shortest ionization energies would certainly be in the bottom left-hand corner of the regular table. The readjust in ionization energies is also bigger going under the regular table (by change within a group) 보다 going across the regular table (by change within a period).
You are watching: Arrange the elements in decreasing order of first ionization energy
So let"s begin from the bottom the the periodic table:#Pb# is the facet that is in the lowest duration at 6 (and lowest group at 14) in the regular table; it"s the the smallest ionization energy.
The period above (5) has actually two of the elements: Sn and also Te. Well, since ionization energy increases throughout a period, Sn will have a smaller sized ionization power than Te.#Pb, Sn, Te#
Now, let"s walk to the third period, wherein #S# and also #Cl# are. Due to the fact that #S# is prior to #Cl,# #S# has a lower ionization energy than #Cl#.#Pb, Sn, Te, S, Cl#
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Ernest Z.
Nov 15, 2016
The bespeak is #"Sn .
Explanation:
You have actually learned the ionization energy increases from optimal to bottom and also from left to appropriate in the routine Table.
You probably saw a chart something favor this.
Here"s the section of the routine Table that has the elements in this question.
You would naturally predict the order come be
#"Pb
This is almost correct, yet the exactly order is #"Sn , as displayed in the picture below.
Why is this so?
The electron configuration of #"Sn"# is #"
The electron construction of #"Pb"# is #"
The #"4f"# electrons in #"Pb"# are poor at shielding the outermost electrons.
Thus the external electrons experience a greater effective nuclear charge, and also it is more complicated to remove them.
Hence #"Pb"# has actually a higher ionization than #"Sn"#, and also the correct order is #"Sn .
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I hope the your instructor told you around this phenomenon prior to asking you to do a prediction.
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