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Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
You are watching: A word or phrase used to show division in a word problem.
At time t = 90 minutes, the bacterial populace was 50000.
Round her sdrta.nets come at least 1 decimal place.
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:
We have the right to use the formula:
A = Ao*2^(t/d); where:
A = amt ~ t time
Ao = early amt (t=0)
t = time period in question
d = doubling time of substance
In ours problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr come 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after ~ 4 hrs
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